Under what condition is it NOT possible for an integer a to be divided by an integer b ?

Mathematics

1 answer:

disa [49]2 years ago

3 0

Answer:

An integer, a, cannot be divided by an integer, b, when $b=0$

Step-by-step explanation:

There is only one limitation when dividing two numbers. This is that you cannot divide a number by 0 as it is impossible to divide something into 0 groups.

As the integer, b, is the number that symbolized the number of groups something is divided into, this value cannot be 0.

You might be interested in

Find the geometric sum: 40 + 20 + 10 + … + 0.078125

sveticcg [70]

$S=40+20+10+\cdots+0.078125$
$S=40\left(1+\dfrac12+\dfrac14+\cdots+\dfrac1{512}\right)$
$S=40\left(1+2^{-1}+2^{-2}+\cdots+2^{-9}\right)$

$2^{-1}S=40\left(2^{-1}+2^{-2}+2^{-3}+\cdots+2^{-10}\right)$

$\implies S-2^{-1}S=40\left(1-2^{-10}\right)$
$\implies\dfrac12S=40\left(1-\dfrac1{1024}\right)$
$\implies S=80\left(1-\dfrac1{1024}\right)=\dfrac{5115}{64}=79.921875$

4 0

2 years ago

15) Yanni received her monthly credit card statement in the mail, the summary of which is shown below. When she

Sergeu [11.5K]

Answer:

D. $3,776.28

Step-by-step explanation:

The finance charge should be ...

$3558.71 × 1.75% = $62.28 . . . . . . not $82.28

The new balance should be $20 less than what is shown, so should be ...

$3,776.28

4 0