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2 years ago

The lengths of the legs of a right triangle are 8 cm and 15 cm.

Mathematics

2 answers:

Serggg [28]2 years ago

7 0

By Pythagorean Theorem, a^2 + b^2 = c^2

so 8^2 +15^2 = c^2

64+225 = 289

sqr rt of 289 is 17

Delvig [45]2 years ago

5 0

Hello, Hopefully this is the answer you are looking for.

Well I got D. 17 cm

If you need the steps I will give them to you :)

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The quadratic formula is:

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and

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Let's identify our a, b, and c values:

a: -1

b: 1

c: 12

Plug in the values for a, b, and c into the equation. Let's do the first equation:

$x=\frac{-1+\sqrt{(1)^2-4(-1)(12)}}{2(-1)}$

Simplify everything in the radical:

$x=\frac{-1+\sqrt{49}}{-2}$

Simplify the radical:

$x=\frac{-1+7}{-2}$

Combine like terms:

$x=\frac{6}{-2}$

Simplify:

$x=-3$

This is one solution, now, let's solve for the other equation:

Since when simplified, everything is the same except the subtraction sign, we can skip the simplification again and change the sign to subtraction:

$x=\frac{-1-7}{-2}$

Combine like terms:

$x=\frac{-8}{-2}$

Simplify:

$x=4$

Your final answers are:

$x=-3$

$x=4$

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