Answer:
The vertex form for a parabola is given by this expression:
By direct comparison we see that for this case:
And we know from the general expression that the vertex is:
So then the vertex for this case is:
Step-by-step explanation:
For this case we have the following function:
And we need to take in count that the vertex form for a parabola is given by this expression:
By direct comparison we see that for this case:
And we know from the general expression that the vertex is:
So then the vertex for this case is:
Answer:
0.42
Step-by-step explanation:
0.42857142857
Answer:
B. y=3(x-1)2 + 3
Step-by-step explanation:
Given that
vertex of the parabola is at the point (1,3)
let's verify, if the option B is the correct equation of the parabola.
comparing to standard equationof parabola (standard quadratic equation), we get
to find the vertex we use formula for x- coordinate as 
to find y put x=1 in the Eq1, we get
vertex =(x,y) = (1, 3)
thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified
Answer:
ok so first ur gonna do 4x3=12 then
Step-by-step explanation:
Write the coeeficientes of the polynomial in order:
| 1 - 5 6 - 30
|
|
|
------------------------
After some trials you probe with 5
| 1 - 5 6 - 30
|
|
5 | 5 0 30
-----------------------------
1 0 6 0 <---- residue
Given that the residue is 0, 5 is a root.
The quotient is x^2 + 6 = 0, which does not have a real root.
Therefore, 5 is the only root. You can prove it by solving the polynomial x^2 + 6 = 0.
