Question

A long solenoid that has 1 080 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00 10-4 T at its center. What current is required in the windings for that to occur?

Answer 1

Answer:

Current, I = 0.073 A

Explanation:

It is given that,

Number of turns in a long solenoid is 1080

Length of the solenoid is 0.420 m

It produces a magnetic field of $10^{-4}\ T$ at its center.

We need to find the current is required in the winding for that to occur. The magnetic field at the center of the solenoid is given by :

$B=\mu_0 NI$

I is current

$I=\dfrac{B}{\mu_o N}\\\\I=\dfrac{10^{-4}}{4\pi \times 10^{-7}\times 1080}\\\\I=0.073\ A$