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Sav [38]
3 years ago
11

A spinning top initially spins at 16rad/s but slows down to 12rad/s in 18s, due to friction. If the rotational inertia of the to

p is 0.0004kg.m2, by how much the angular momentum of the top changes?
Physics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

The  change  in angular momentum is \Delta  L  = 0.0016 \ kgm^2/s

Explanation:

From the question we are told that

      The initial angular velocity of the spinning top is  w_1  =  16 \ rad/s

      The angular velocity after it slow down is  w_2 =  12 \ rad/s

      The time  for it to slow down is  t =  18 \ s

       The rotational inertia due to friction is  I =  0.0004 \ kg \cdot m^2

 Generally the change in the angular momentum is  mathematically represented as  

         \Delta  L  =  I  *(w_1 -w_2)

substituting values  

        \Delta  L  =  0.0004  *(16 -12)

       \Delta  L  = 0.0016 \ kgm^2/s

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Volcanologists and seismologist are specialzed in what
antiseptic1488 [7]

The answer is:

They are specialized in geology and geophysics

1) Volcanologists are scientific researchers who study the properties of volcanoes and develop the science of predicting volcanic eruptions accurately.

- Volcanoes are the results of fissures in the earth's crust, from which magma, gases, rocks, and ashes can erupt.  


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A) Volcanologists are scientists who use a variety of sophisticated equipment to measure and analyze volcanic activity, lava, rock, ashes and gases as well as earthquakes caused by eruptions.


B) Also, they measure the magnitude and intensity of explosions, placing them on a scale from 1 to 8 [volcanic explosivity index].  


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5 0
3 years ago
Read 2 more answers
Would u rather/content creator or a rap artist
BartSMP [9]

a content creator because if i was a rapper i probably wouldn't make good songs lol

7 0
2 years ago
The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this
antiseptic1488 [7]

Answer:

<h3>14.97m/s</h3>

Explanation:

Given

Initial velocity of the car u = 8m/s

Distance travelled by the rider S = 40m

Acceleration a = 2m/s²

Required

rider's velocity after the acceleration v

Using the equation of motion

v² = u²+2as

v² = 8²+2(2)(40)

v² = 64+160

v² = 224

v = √224

v = 14.97m/s

Hence the rider's velocity after the acceleration is 14.97m/s

5 0
2 years ago
Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800c. Mavis and Stanley start timers at zero when t
inna [77]

Answer:

Explanation:

a. The equation of Lorentz transformations is given by:

x = γ(x' + ut')

x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.

x' = 0

t' = 5.00 s

u =0.800 c,

c is the speed of light = 3×10⁸ m/s

Then,

γ = 1 / √ (1 - (u/c)²)

γ = 1 / √ (1 - (0.8c/c)²)

γ = 1 / √ (1 - (0.8)²)

γ = 1 / √ (1 - 0.64)

γ = 1 / √0.36

γ = 1 / 0.6

γ = 1.67

Therefore, x = γ(x' + ut')

x = 1.67(0 + 0.8c×5)

x = 1.67 × (0+4c)

x = 1.67 × 4c

x = 1.67 × 4 × 3×10⁸

x = 2.004 × 10^9 m

x ≈ 2 × 10^9 m

Now, to find t we apply the same analysis:

but as x'=0 we just have:

t = γ(t' + ux'/c²)

t = γ•t'

t = 1.67 × 5

t = 8.35 seconds

b. Mavis reads 5 s on her watch which is the proper time.

Stanley measured the events at a time interval longer than ∆to by γ,

such that

∆t = γ ∆to = (5/3)(5) = 25/3 = 8.3 sec which is the same as part (b)

c. According to Stanley,

dist = u ∆t = 0.8c (8.3) = 2 x 10^9 m

which is the same as in part (a)

7 0
2 years ago
A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
PIT_PIT [208]

Their velocity afterward is  v=3.467 m/s

Explanation:

Given:

Mass of the first football player= 91.5 kg

Initial velocity of the football player 3.73 m/s

Mass of second football player=63.56 kg

Initial velocity of the second football player=3.09 m/s

To find:

Final velocity of both players=?

Solution:

According to the law of conservation of momentum,

Initial momentum =final momentum

mathematically represented as  

m_1u_1+m_2u_2=m_1v_1+m_2v_2...........................(1)

where

u_1=intial velocity of the football player

u_2 = inital velocity of second football player

v_1=finall velocity of the  first football player

v_2=final velocity of second football player

after tackling , both the football players moves with the same velocity,

so v_1=v_2=v

Hence equation (1) becomes

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}

now substituting the values,

v=\frac{(91.5\times+3.73)+(63.5\times3.09)}{(91.5+63.5)}v=\frac{(341.29+196.210)}{155}

v=\frac{537.5}{155}

v=3.467 m/s

7 0
3 years ago
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