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Juli2301 [7.4K]
3 years ago
13

Why is it difficult to convince top management to commit funds to develop and implement a Strategic Information System

Computers and Technology
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

It is difficult to <u>convince top management </u>to commit funds to develop and implement an SIS because it can lead to reengineering, which requires businesses to revamp processes to undergo organizational change to gain an advantage.

Explanation:

You might be interested in
The blank contains the computer's brain the central processing unit CPU
Ipatiy [6.2K]

The central processing unit (CPU), also called a processor, is located inside the computer case on the motherboard. Hope it helps (:

6 0
3 years ago
1. Define lexemes. Give an example of an lexeme in any programming language.<br>​
tresset_1 [31]

The correct answer is; " a unit of lexical meaning that underlies a set of words that are related through inflection."

Further Explanation:

The lexeme is part of the stream where the tokens are taken and identified from. When these streams become broken, there is always an error message. The lexeme is known as "the building blocks of language."

These are a very important part of computer programming. If any string or character is misplaced this can stop the entire program or operation.

One example of a lexeme is;

  • the symbols (, ), and -> are for the letter C.

Learn more about computer programming at brainly.com/question/13111093

#LearnwithBrainly

4 0
3 years ago
) how many bits are used for host number on the child network (subnet) , b) how many usable addresses can exist on this child ne
vovikov84 [41]

Answer:

Machine’s IP=126.127.85.170, Machine’s Netmask=/27, Parent’s Netmask=255.255.240.0 .

a) Machine's Netmask = /27 : therefore no. of remaining bits for hosts =32-27 = 5 bits.

b) No. of usable addresses in the child network = 25 -2 = 32-2 =30 [Since first(network ID of the machine) and last ip (broadcast address of the machine ) addresses are not used ]

c) first usable address is on this child network (subnet) =

First, find out the network id of machine can be found out by doing bitwise AND machine's IP and Machine's subnet mask :

01111110. 01111111.01010101.10101010 (IP)

11111111. 11111111 .11111111 .11100000 (Subnet Mask)

01111110. 01111111. 01010101.10100000 (Network ID )

first usable address is on this child network (subnet) :   01111110. 01111111. 01010101.10100001

: 126.127.85.161

d) what the last usable address is on this child network (subnet) :  01111110. 01111111. 01010101.10111110

: 126.127.85.190

e) what the child network’s (subnet's) broadcast address is :

In the directed broadcast address , all the host bits are 1. Therefore, broadcast address :

01111110. 01111111. 01010101.10111111 (126.127.85.191)

f) what the child network's (subnet's) network number is : Network ID has already been calcuulated in part c .

01111110. 01111111. 01010101.10100000 (126.127.85.160)

6 0
3 years ago
cout &lt;&lt; "Part 1" &lt;&lt; endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac
Margarita [4]

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

 

}

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

 

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

 

 

 

 

// This will print the number of evens in the array.

cout << endl << evens;

 

cout << "\nPart 4" << endl;

 

int total;

 

total=computeTotalOdds(array1,numElements);

cout << endl << total;

 

return 0;

}

3 0
3 years ago
As a final lesson to her team, Katie shows them a job that has already been preflighted and is now getting ready to be sent to t
Vsevolod [243]

Answer:

Printed

Explanation:

The job was finished and sent to the printer. In the printer, you have to waite to be printed

5 0
3 years ago
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