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Whitepunk [10]
3 years ago
5

What's 15 rounded to the nearest whole number

Mathematics
2 answers:
nadezda [96]3 years ago
8 0

Answer:

15

Step-by-step explanation:

15 itself is a whole number

hence 15 rounded to the nearest whole number is still 15.

yawa3891 [41]3 years ago
4 0

The next larger whole number is 16.

The next smaller whole number is 14.

Nether of those is any closer to 15 than 15 already is.

So the whole number nearest to 15 is <em>15 itself</em>.

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A sample of 16 cookies is taken to test the claim that each cookie contains at least 9 chocolate chips. The average number of ch
alexandr1967 [171]

Answer:

(a) The value of z test statistics is -2.25.

(b) At 0.05 significance level the z table gives critical value of -1.645 for left-tailed test.

(c) The p-value for this test statistic is 0.0122.

(d) We conclude that the average number of chocolate chips in all the cookies is less than 9.

Step-by-step explanation:

We are given that a sample of 16 cookies is taken to test the claim that each cookie contains at least 9 chocolate chips.

The average number of chocolate chips per cookie in the sample was 7.875. The standard deviation of the population is 2.

Let \mu = <em><u>the average number of chocolate chips in all the cookies</u></em>.

So, Null Hypothesis, H_0 : \mu \geq 9     {means that the average number of chocolate chips in all the cookies is at least 9}

Alternate Hypothesis, H_A : \mu < 9     {means that the average number of chocolate chips in all the cookies is less than 9}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                     T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean number of chocolate chips per cookie = 7.875

           \sigma = population standard deviation = 2

           n = sample of cookies taken = 16

So, <u><em>the test statistics</em></u>  =  \frac{7.875-9}{\frac{2}{\sqrt{16} } } 

                                     =  -2.25

(a) The value of z test statistics is -2.25.

(b) <u>Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test.</u>

Since our test statistic is less than the critical value of z as -2.25 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

(c) The P-value of the test statistics is given by;

             P-value = P(Z < -2.25) = 1 - P(Z \leq 2.25)

                           = 1 - 0.9878 = <u>0.0122</u>

(d) Therefore, we conclude that the average number of chocolate chips in all the cookies is less than 9.

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3 years ago
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