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Oksanka [162]
3 years ago
12

Which expression is not equivalent to the opposite of +9?

Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer:

D. |-9|

Step-by-step explanation:

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(4m+7n-6p)-(2m-3n-4p)
Vanyuwa [196]

Answer:

2m + 10n - 2p

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Terms

Step-by-step explanation:

<u>Step 1: Define</u>

(4m + 7n - 6p) - (2m - 3n - 4p)

<u>Step 2: Simplify</u>

  1. Distribute negative:                    4m + 7n - 6p - 2m + 3n + 4p
  2. Combine like terms (m):             2m + 7n - 6p + 3n + 4p
  3. Combine like terms (n):              2m + 10n - 6p + 4p
  4. Combine like terms (p):              2m + 10n - 2p
6 0
2 years ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{adjacent}{hypotenuse}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{opposite}{adjacent}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{adjacent}{opposite}&#10;\\\\\\&#10;% cosecant&#10;csc(\theta)=\cfrac{hypotenuse}{opposite}&#10;\qquad \qquad &#10;% secant&#10;sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{\sqrt{35}}{6}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{-1}{\sqrt{35}}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{\sqrt{35}}{1}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
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WILL MARK BRAINLIEST!! 5 POINTS!!
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The speed of the car per minute is 3,520 feet (choice c). This is because in order to solve the problem, you have to convert 40 mi/h into feet. Since there are 5,280 feet per mile, you have to do 5,280 x 40, which is 211,200, which is the number of feet per hour. But, the question is asking for ft/min. There are 60 minutes in an hour, so you divide 211,200 by 60, which is 3,520. So, the speed of the car per minute is 3,520 feet.
5 0
3 years ago
Read 2 more answers
At Garcia's Bike Rentals, it costs $13 to rent a bike for 3 hours. How many dollars does it cost per hour of bike use?
Naily [24]

Answer:

$4.33

Step-by-step explanation:

3 hours -> $13

1 hour -> $13/3 = $4.33

5 0
3 years ago
56/(7-9)^3-25/23-5*4
meriva
I got -28.08695652. It doesn't repeat nor does it terminate
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3 years ago
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