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wolverine [178]
3 years ago
9

What is 38,107 in exponential form

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0
30,000+8,000+100+7 that’s the answer
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Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ
In-s [12.5K]
PART A

The equation of the parabola in vertex form is given by the formula,

y - k = a {(x - h)}^{2}

where

(h,k)=(1,-2)

is the vertex of the parabola.

We substitute these values to obtain,


y  + 2 = a {(x - 1)}^{2}

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.


6  + 2 = a {(3 - 1)}^{2}


8= a {(2)}^{2}


8=4a


a = 2
Hence the equation of the parabola in vertex form is


y  + 2 = 2 {(x - 1)}^{2}


PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

y  + 2 = 2{(x - 1)}^{2}

This implies that

y + 2 = 2(x - 1)(x - 1)


We expand to obtain,


y + 2 = 2( {x}^{2}  - 2x + 1)


This will give us,


y + 2 = 2 {x}^{2}  - 4x + 2


y =  {x}^{2}  - 4x

This equation is now in the form,

y = a {x}^{2}  + bx + c
where

a=1,b=-4,c=0

This is the standard form
7 0
3 years ago
For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 for each 1/2 mile or fraction of 1/2 miles. If, for every
nydimaria [60]

Answer:

E: 2.00 + 0.75 [ 2r]

Step-by-step explanation:

r represents the number of miles. For each 1/2 mile the taxi will charge and extra free of $0.75. Then, for each mile, the taxi will charge $0.75*2. For example:

For a trip of 1 mile the taxi will charge:

$2.00+$0.75*2

For a trip of 2 miles, the taxi will charge:

$2.00+0.75*4

For a trip of 10 miles, the taxi will charge:

$2.00+$0.75*20

Notice that the variable fee (the one that depends on the number of miles) is $0.75 times the double of miles. In each case the number of miles is multiplied by two. Then the correct answer is E: 2.00 + 0.75 [ 2r]

5 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
How are decimals 0.009 and 0.09 related?
saveliy_v [14]
Because 0.09 is ten times as big as 0.009
7 0
3 years ago
Rewrite the following polynomial in standard form <br> -x2 + 1 + 2x
fenix001 [56]

Answer:

-5x^4+8x^3-2x+1

Step-by-step explanation:

5 0
3 years ago
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