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qaws [65]
3 years ago
14

True or False: The hypotenuse is the longest side of a right triangle. A) yes B) no

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0
Answer = A.) yes!
This statement is True
The hypotenuse is the longest side of a triangle. 
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3 years ago
Form an equation whose roots are 1/2 and -1/3.
tensa zangetsu [6.8K]
Well a root means that y will equal zero when x is that root number. we are given the roots. So when x = 1/2 or -1/3 then y = 0.

it has to be quadratic with an x^2 since it has 2 roots. So we will write basic formula

y = (x + a) (x + b)

in this basic quadratic the opposite of a and b will be roots. this means negative a and negative b are roots or -a and -b are roots.

so we can fill in our roots for a and b if we want but.remember we.have to use the opposite of.our roots because we.use -a and -b.

so let's fill in our opposite.roots for.a and.b

y = (x + (-1/2)) (x + (-(-1/3)))

since I have two negatives in front of the 1/3 it becomes positive.. So

y = (x - 1/2)(x + 1/3)

this is an equation with those roots. You can multiply it out if necessary.

y = x^2 - 1/6x - 1/6

I think that's what it comes out to.

7 0
3 years ago
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Which of the following constants can be added to x^2 + 2/3x to form a perfect square trinomial?
Angelina_Jolie [31]
Hello.

A trinomial is a perfect square if the square root of the first term times the square root of the third term times 2 equals the middle term.

\boxed{\mathsf{x^{2} + \dfrac{2}{3} x}}

a) Adding 1/9:

\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{1}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{1}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2}{3} x \rightarrow it \: is \: a \: perfect \: square \: trinomial}

b) Adding 4/9:

\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{4}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{4}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{2}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{4}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}

c) Adding 4 and 1/9:

\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9} + 4 = x^{2} + \dfrac{2}{3} x + \dfrac{37}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{37}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{\sqrt{37}}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2\sqrt{37}}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}

Hope I helped.
3 0
3 years ago
PLSSSSSSS HELP will crown brainliest!!!!!!!
deff fn [24]
2: A = b*h
    A = 4.5*14
    A = 63 m^2
3: A = 1/2*b*h
    A = 1/2*4*13
    A = 2*13 = 26 in^2
3 0
3 years ago
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