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GenaCL600 [577]
3 years ago
9

Help asap !! will get branliest.​

Mathematics
1 answer:
kompoz [17]3 years ago
7 0

Answer:

0.8

Step-by-step explanation:

(2 x 10^-4)

= 0.0002

(4x10^3)

= 4000

0.0002 x 4000 = 0.8

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Shade in some or all of the grids to show that 2 ones is the same as 20 tenths
scZoUnD [109]
Given three grids with each grid representing one whole.
Each grid represents 1 ones and each vertical bar of a grid represent 1 tenth.
There are 10 vertical bars in each grid, hence each grid represent 1 ones = 10 tenths and 2 grids represent 2 ones = 20 tenths.

Therefore, two complete grids are to be shaded to <span>show that 2 ones is the same as 20 tenths</span>
4 0
3 years ago
Simplify the expression below.
natita [175]

Answer:

3m - 8

Step-by-step explanation:

Step by Step:

Equation= 6m³ - 16m² + 15m - 40/ 2m² + 5

Factor out 2m² from 6m³ - 16m²:

Factor out 5 from expression:

2m²(3m - 8) + 5(3m - 8)/2m² + 5

Factor out 3m - 8:

(3m - 8)(2m² + 5)/2m² + 5

Rude the fraction with 2m² + 5:

3m - 8 is the answer

I hope this helped!

3 0
3 years ago
A ruler is used to measure the width of the spine of a book.
sp2606 [1]

Answer:

1.00 cm Is the greatest level of precision possible for the measurement of the width of the spin of the book

3 0
3 years ago
Pls help :)) this question is confusing for me :)
Temka [501]

Given:

y^{2}(2 y-5)-8 y+20

To find:

The product of the expression.

Solution:

y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)

Take out -4 as a common factor in Last two terms.

                                =y^{2}(2 y-5)-4(2 y-5)

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

                                =(2 y-5)(y^{2}-4)

4 can be written as 2².

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Using the identity: (a^2-b^2)=(a-b)(a+b)

                                =(2 y-5)(y-2)(y+2).

The product is (2 y-5)(y-2)(y+2).

5 0
3 years ago
What is the standard equation centered at the orginwith radius r?
creativ13 [48]
The equation of circle with center as origin O and radius r,
{x}^{2} + {y}^{2} = {r}^{2}
6 0
3 years ago
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