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Usimov [2.4K]
3 years ago
12

20 PTS

Mathematics
1 answer:
Katen [24]3 years ago
5 0

Answer:

it's ok to be in the picture right

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(x4 − 9x + 5x7) + (5x − 10 + 3x4 − 2x2)
Svetlanka [38]

Answer:

(x^4 - 9·x + 5·x^7) + (5·x - 10 + 3·x^4 - 2·x^2)

x^4 - 9·x + 5·x^7 + 5·x - 10 + 3·x^4 - 2·x^2

5·x^7 + x^4 + 3·x^4 - 2·x^2 - 9·x + 5·x - 10

5·x^7 + 4·x^4 - 2·x^2 - 4·x - 10

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3 years ago
What are the roots of this quartaic equation?<br> -102 + 12r - 9 = 0
elena-14-01-66 [18.8K]

Answer:

r = \frac{37}{4}  

I hope this helps!

7 0
3 years ago
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The mean for these digits are 3
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3 years ago
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find the roots of the quadratic equation x^2-6x+k=0.giventhat one root is three times the other and that k is a constant.Also fi
arlik [135]

x_{1}  = 3x_{2}  \\ x_{1}  - 3x_{2}  = 0 ←relation \: 1\\ x_{1}  + x_{2}  = 6 ←relation \: 2

(x_{1},x_{2}) : (4.5,1.5)

k = x_{1}x_{2} = 4.5 \times 1.5 = 6.75

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Please help! I will mark as brainliest IF answer is right. &lt;3
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Answer:

b^2 + 3b - 4 + 4/(b-2)

Step-by-step explanation:

see pic

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