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asambeis [7]
3 years ago
9

Write a function file that accepts the values of r, a and n as arguments and uses a for loop to return the sum of the first n te

rms of the geometric series. test your function for a = 3, r = 1/2 and n = 10.
Computers and Technology
1 answer:
Murrr4er [49]3 years ago
7 0

Given, a = 3, r = 1/2, n = 10

%r is common ratio

%n is number of terms

%a is the first term of the series

Sum = 0;

a = 3;

r = 1/2;

for i = 0 : 1 :  10;

Sum = Sum + a * r ^ i;

end

Sum


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given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i < j < a.length), such that a[
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Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

<em>// C++ program for the above approach</em>

<em> </em>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em> </em>

<em>// Function to find the count required pairs</em>

<em>void getPairs(int arr[], int N, int K)</em>

<em>{</em>

<em>    // Stores count of pairs</em>

<em>    int count = 0;</em>

<em> </em>

<em>    // Traverse the array</em>

<em>    for (int i = 0; i < N; i++) {</em>

<em> </em>

<em>        for (int j = i + 1; j < N; j++) {</em>

<em> </em>

<em>            // Check if the condition</em>

<em>            // is satisfied or not</em>

<em>            if (arr[i] > K * arr[j])</em>

<em>                count++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << count;</em>

<em>}</em>

<em> </em>

<em>// Driver Code</em>

<em>int main()</em>

<em>{</em>

<em>    int arr[] = { 5, 6, 2, 5 };</em>

<em>    int N = sizeof(arr) / sizeof(arr[0]);</em>

<em>    int K = 2;</em>

<em> </em>

<em>    // Function Call</em>

<em>    getPairs(arr, N, K);</em>

<em> </em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ4

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