Explanation:
On October 31, around twelve o'clock at night, the lights were dull. It was Siberian cold and I was walking painfully under the whitish lighting of a lamppost and the retro neon lights of a convenience store in a neighborhood that was buzzing when I went to buy meat. buildings, grayish in this half-light, crumbled under the weight of sleep, while the neighborhood was still open. Its decoration was particularly macabre in tone: synthetic but very sticky spider webs adorned the porches of the terraces, pumpkin ornaments are exhibited like works of art, ... Some pushed the macabre by hanging mannequins made up in corpses. At the entrance to the neighborhood, I found the body of its owner stabbed. Frozen in place, I wondered what else awaits me. My heart was pounding, feeling a shiver of anguish. When I was removing the phone from my pocket to call my police friends, my hands were clenched in fear. An investigation was carried out to find out the causes of death. Also, I went with them so they take my words. Hopefully the murderer will be arrested to put an end to this sybilinous crime.
Answer:
flight stimulators are used to train astronaut and design simple air craft
Answer:
A lookaside buffer translation (TLB) is a memory cache that reduces the time it takes to access a user memory place. TLB includes the most lately used page table entries.
TLB is used to overcome the issue of sizes at the time of paging. Page Table Entry (PTE) is used for framing the memory ,but it uses two references one for finding the frame number
and the other for the address specified by frame number.
<u>Formula for finding effective memory access time-</u>
Effective Memory Access Time = (TLB access_time+Memory Access Time)*hit ratio + (TLB access_time+2*Memory Access Time)*(miss ratio)
Given in question,
Hit ratio = 0.90
Memory Access Time = 150ns
TLB access time= 5ns
Effective Memory Access Time = (TLB access_time+Memory Access Time)*hit ratio + (TLB access_time+2*Memory Access Time)*(miss ratio)
=(5+150) * 0.90 + (5+2*150)*(1-0.90)
=155 * 0.90 + (305*0.1)
=139.5 + 30.5
= 170ns
1. 3 times the light voltage, ie., 3*0.5 = 1.5V
2. Total R = 3*25 = 75Ω, V=1.5V, I = V/R = 1.5/75 = 20 mA
3. A 1.5V battery (e.g., an AA battery) with a charge of at least 20mAh. AA batteries should be able to handle this easily.
Answer:
Its data sets are at least a petabyte in size.
Explanation:
Big data data sets are of huge size to perform the computations using modern techniques.
