A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:

Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1





We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height
Put height value in equation 1







Therefore ,time interval of camera film him is 
Answer:
look the photo
Step-by-step explanation:
..0000000000000000
Answer:
108, 108, 72
Step-by-step explanation:
Vertical angles are congruent and if the measure of 1 of the angles is 72 degrees and straight lines equal 180 degrees you have to subtract 72 from 180 which equals 108.
Yes. Slope = rise over run so you go up one, over five
Answer:
6
Step-by-step explanation:
24 = 2L + 2(6), multiply...
24 = 2L + 12, subtract 12 to both sides...
12 = 2L, divide 2 to both sides to isolate the varibale L
6 = L
Therefroe, L = 6