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2 years ago

14

How many students tired out for the volleyball team is this a statistical or no

1 answer:

vodomira [7]2 years ago

4 0

That question is not a statistical question since there will be only one answer. If it were to be statistical it would have multiple answers an example of that type of question would be, Why did you decide to try out for the volleyball team? This is statistical because some could say they joined for fun, credits, to do something active, etc.. there would be multiple answers. Your question, How many students tried out for the volleyball team isn't statistical since it will have one answer such as, 26 students, 15 student, 2 students, etc...

Hope this helped!

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2 years ago

1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the

Musya8 [376]

Answer:

A) 34.13%

B) 15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

$z=\frac{x-m}{s}$

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

$z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0$

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

= 0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

$P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587$

C) Between 80 and 120

$P( 80$

D) less than 80

$P( x < 80 ) = P( z$

E) Between 70 and 100

$P( 70$

F) More than 130

$P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013$

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2 years ago