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3 years ago

How many students tired out for the volleyball team is this a statistical or no

1 answer:

4 0

That question is not a statistical question since there will be only one answer. If it were to be statistical it would have multiple answers an example of that type of question would be, Why did you decide to try out for the volleyball team? This is statistical because some could say they joined for fun, credits, to do something active, etc.. there would be multiple answers. Your question, How many students tried out for the volleyball team isn't statistical since it will have one answer such as, 26 students, 15 student, 2 students, etc...

Hope this helped!

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This is 8th grade math please

VladimirAG [237]

Answer: 1/2(m<TUV)= m<TUW

Step-by-step explanation: If you divide TUV by 2 then you would get 28 degrees which would be The < TUW

4 0

3 years ago

Read 2 more answers

Can someone confirm this? is it correct?

EastWind [94]

<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>

8 0

3 years ago

Solve the following absolute value equation.<br><br> −8 − 2 |5X – 17| = −14

Levart [38]

If 5x - 17 ≥ 0, then |5x - 17| = 5x - 17 and the equation reduces to

-8 - 2 (5x - 17) = -14

-8 - 10x + 34 = -14

-10x = -40

x = 4

If 5x - 17 < 0, then |5x - 17| = -(5x - 17) = -5x + 17 and we have

-8 - 2 (-5x + 17) = -14

-8 + 10x - 34 = -14

10x = 28

x = 2.8

4 0

2 years ago

Write the log equation as an exponential equation. You do not need to solve for x.

Archy [21]

the answer is - 1/4

4 0

3 years ago

3. Use the diagram to answer the following questions.

Nuetrik [128]

Answer:

See explanation

Step-by-step explanation:

A. There are 8 points: A, B, C, D, E, F, G and H

B. There are 9 lines in the figure: AB, BC, AC, DE, DF, EF, BE, AD and CF

C. There are 5 planes in the figure: ABC, DEF, ABED, ACFD and BEFC

D. Three points are collinear if they lie on the same line. Collinear points are D,G and F or C,H and F

E. Coplanar points are those which lie in the same plane. Coplanar points are B, E, F and C or A, C, F and D or A, B, E and D or other combinations of four points lying in the same plane

I. Planes ABC and ABE intersect by a line AB

G. Planes BCH and DEF intersect by a line EF

H. Lines AD and DF intersect at a point D

4 0

3 years ago