A navy cruiser detects a nuclear submarine that is 2500 feet from the cruiser. The angle between the water level and the submari
1 answer:
Answer:
Depth of the submarine = 668.09 feet
Step-by-step explanation:
From the figure attached,
In triangle ABC,
Distance between a navy cruiser and a nuclear submarine = 2500 feet
Angle between the water level and the submarine = 15.5°
By applying sine rule in the given triangle,
sin(∠BAC)° =
sin(15.5°) =
BC = 2500[sin(15.5)]
BC = 668.09 feet
Therefore, submarine is 668.09 feet deep in the sea.
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Answer:
The percentage of people should be seen by the doctor between 13 and
17 minutes is 68% ⇒ 2nd term
Step-by-step explanation:
* Lets explain how to solve the problem
- Wait times at a doctor's office are typically 15 minutes, with a standard
deviation of 2 minutes
- We want to find the percentage of people should be seen by the
doctor between 13 and 17 minutes
* To find the percentage we will find z-score
∵ The rule the z-score is z = (x - μ)/σ , where
# x is the score
# μ is the mean
# σ is the standard deviation
∵ The mean is 15 minutes and standard deviation is 2 minutes
∴ μ = 15 , σ = 2
∵ The people should be seen by the doctor between 13 and
17 minutes
∵ x = 13 and 17
∴ z =
∴ z =
- Lets use the standard normal distribution table
∵ P(z > -1) = 0.15866
∵ P(z < 1) = 0.84134
∴ P(-1 < z < 1) = 0.84134 - 0.15866 = 0.68268 ≅ 0.68
∵ P(13 < x < 17) = P(-1 < z < 1)
∴ P(13 < x < 17) = 0.68 × 100% = 68%
* The percentage of people should be seen by the doctor between
13 and 17 minutes is 68%