In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
First you compare the denomonators and see if they have any common multiples, then what you do to one side you do to the other so you multiply so you get the same number on both denomonators.finally you multipybthe same number you did ti he botto. to the top.p.s. your welcome
We can distribute the negative to get 8 + 6i + 2 - 7i, and we can simplify that to get 10 - i.
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Hope this helps!
Answer:
x =68
Step-by-step explanation:
The sum of the angles of a triangle are 180
37+75+x = 180
Combine like terms
112+x = 180
Subtract 112 from each side
112+x-112=180-112
x =68
