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Bad White [126]
3 years ago
9

RELATED QUESTION..........

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

BCGF is a quadrilateral, angles sum to 360 degrees.

B+C+G+F=360

B and G are right angles, formed by a radius and a tangent.  

90+C+90+F=360

C+F=180

C and F are supplementary.

2x + 146 + 4x + 238 = 180

6x + 384 = 180

6x = -204

x = -34

Answer: -34, second choice

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Choose all that define a rectangle in the coordinate plane by the four given points
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The answer is A.

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By labelling the four points on a coordinate grid and connecting them, you will get the shape of a rectangle.

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What is the average of 5/6, 2/3, and 1/2?
Sloan [31]
(5/6 + 2/3 + 1/2)/3 = 2/3 = 0.66
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Burnem Inc. manufactures thumb drives and sells them to a distributor. Burnem's total cost and total revenue (in dollars) for x
AlladinOne [14]

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444 thumb drives

Step-by-step explanation:

Break even is the point at which the proceeds are equal to the costs i.e. when Total cost = Total revenue. So using the equations provided, the breakeven point for Burnem Inc. will be 4x + 4884 = 15x, where x is number of thumb drives. We solve for x to get the answer:

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3 years ago
Let C represent the number of hours when the sky is cloudy and L represent the number of hours when the sky
bixtya [17]

Answer:

Step-by-step explanation:A large solar panel can generate power at a maximum rate of 400400400 kilowatts per day. It generates power at a constant rate when the sky is cloudy, and it generates power at a constant rate when the sky is clear. Let CCC represent the number of hours when the sky is cloudy and LLL represent the number of hours when the sky is clear during which the solar panel can generate power without exceeding its capacity. 5C+32L \leq 4005C+32L≤4005, C, plus, 32, L, is less than or equal to, 400 According to the inequality, at what rate does the solar panel generate power when the sky is cloudy, and at what rate does it generate power when the sky is clear?

2

5 0
3 years ago
Please help asap i’m stupid
nevsk [136]

Answer:

74

Step-by-step explanation:

Say that arc JL going through M is arc E and JL going the other way is arc D

For the angle formed by two tangents, K=(1/2)(E-D)

64=E-D

Furthermore, angle K and central angle JCL (facing toward K) are supplementary, so 180-K=JCL=180-32=148

Thus, as the angles around angle C add up to 360, angle JCL (facing toward M) is 360-148=32+180=212

E is then 212

64=212-D

212-64=D=148

Thus, as JML is an inscribed angle, M=1/2(D)=1/2(148)=74

3 0
4 years ago
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