Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation:
Answer:
3/2
Step-by-step explanation:
because the equations y 2 - y 1 over x 2 - x 1 is 4-1 over 2-0 and that is 3/2
You can look at -32 as being -2^5 so if you write (-2^5)^3/5 the 5's cancel out making it -2^3 which equals -8
You distribute the -4 with the -8x and -8 which results in 32x+32.
