Answer: False
=============================================
Explanation:
I'll use x in place of p.
The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.
Compare this to ax^2+bx+c = 0
We have
Plug those three values into the discriminant formula below
d = b^2 - 4ac
d = (-5)^2 - 4(10)(8)
d = 25 - 40*8
d = 25 - 320
d = -295
The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".
Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.
Answer:
y=8
Step-by-step explanation:
Point slope is y2-y1 over x2-x1
So its 8-(-6) over 8-8 which equals 14/0 which means the equation of the line is y=8
This is a horizontal line on 8 on the y axis
Answer:
The answer is 4
Step-by-step explanation:
x^2-2x-8=1/4x-1
x^2-9x/4-7=0
4x^2-9x=28
Therefore if we take value of x as 4 aur eq.get balanced...