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2 years ago

HELP NEEDED!!! NOW PLZ

Mathematics

1 answer:

liq [111]2 years ago

3 0

Answer:

frick

Step-by-step explanation:

chicken jencdcdhchdbbchdcdccdc

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NEED HELP ASAP<br> !!!!!!!

poizon [28]

Answer:

P = 184 yards

C = 175.84 centimetres

P = 212 m

Step-by-step explanation:

P = 2(150 yards) + 2(92 yards)

P = 300 yards + 184 yards

P = 184 yards

C = 2(3.14) × (28 centimetres)

C = 6.28 × (28 centimetres)

C = 175.84 centimetres

P = 104 m + 32 m + 76 m

P = 212 m

6 0

2 years ago

The gravitational force produced between any two objects kept 2.5×10^4 km apart is 580 N . At what distance should they be kept

DochEvi [55]

Answer:

Formula for gravitational force F = G M1 * M2 / R^2 where G is the gravitational constant

F2 / F1 = (R1 / R2)^2 = 1/2 where F2 is the required force

R2 = (2)^1/2 R1 distance for R2 to be 1/2 force at R1

Since force is proportional to the square of the distance of separation, increasing the distance of separation by 2^2 will halve the force

7 0

2 years ago

The area of a rectangular rug is given by the trinomial r^2-4r-77. What are the possible dimensions of the rug? Use factoring.

Softa [21]

When you factor the equation...

r^2-4r-77

r^2+7r-11r-77

r(r+7)-11(r+7)

(r-11)(r+7) so each parenthetical term is a dimension.

Note that r>11 though for any possible real solution.

4 0

3 years ago

The larger number is 18 more than twice the smaller. If the sum of the two numbers is 93, find both numbers

Ganezh [65]

Answer:

larger number=18+(2x)

smaller number=x

(18+2x)+x=93

18 +3x=93

3x=93-18

3x=75

x=25

18+2(25)

18+50

larger number =68

smaller number=25

6 0

2 years ago

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago