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il63 [147K]
4 years ago
8

Chris needs at least a C+ average to pass his math class. His test grades in the class are shown below. 68, 80, 73, 72 The lowes

t C+ grade is 76. If there are only 5 tests, what is the minimum grade that Chris needs to get on his last test? A. 97 points B. 89 points C. 85 points D. 87 points
Mathematics
2 answers:
sp2606 [1]4 years ago
8 0

Answer:

B 89 points

Step-by-step explanation:

you calculate the mean, basically trial and error. So you add one of the answers to 68+80+73+72 and then divide by 5 because there are five tests

hope this helped<33

o-na [289]4 years ago
6 0

Answer:

C

Step-by-step explanation:

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3 years ago
Need help on this question i dont get it ima be posting some more but i need help on this on first
Anuta_ua [19.1K]

Answer:

The answer is B.

Step-by-step explanation:

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8 0
3 years ago
-6 - 3(2x + 4) = 18what’s the answer
Brrunno [24]

Answer:

x=-6

Step-by-step explanation:

-6-3\left(2x+4\right)=18

Add 6 to both sides:

-6-3\left(2x+4\right)+6=18+6

-3\left(2x+4\right)=24

Divide both sides by -3:

\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}

2x+4=-8

Subtract 4 from both sides:

2x+4-4=-8-4

2x=-12

Divide both sides by 2:

\frac{2x}{2}=\frac{-12}{2}

x=-6

7 0
3 years ago
The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

8 0
4 years ago
Find the indicated values, where g(t)=t^2-t and f(x)=1+x f(2g(1)
Darina [25.2K]

g(t)=t^2-t\\\\f(x)=1+x\\\\f(2g(1))=?\\\\g(1)=\\_{\text{put t=1 to the equation of g(t)}}\\\\=1^2-1=1-1=0\\---------------\\2g(1)=2(0)=0\\\\f(2g(1))=\\_{\text{put x-0 to the equation of f(x)}}\\\\=1+0=1\\\\Answer:\ f(2g(1))=1

8 0
3 years ago
Read 2 more answers
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