The graph of g(x) = f(-5x+10) is given in the figure.
<h3>What is a graph?</h3>
A diagram showing the relation between two variable quantities,each measured along one of a pair of axes at right angles.
It is given that f(x) = x^2
and g(x ) = f(-5x+10)
Now putting the value of f(x) in g(x) we get,
g(x) = f(-5x+10) = (-5x+10)^2
So, g(x) = (-5x+10)^2
now, making the table for g(x),
<u><em>x </em></u><u>g(x)</u>
0 100
1 81
2 0
3 25
4 100
5 225
Hence,the graph of g(x) = f(-5x+10) is given in the figure.
More about graph :
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Answer:
-1.5
Step-by-step explanation:
3/8 is 0.375 in decimal form
Answer:
64.53
Step-by-step explanation:
56.213 rounds to 56.21
7.983 rounds to 7.98
0.344 rounds to 0.34
Next you do 56.21 + 7.98 + 0.34 = 64.53
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
