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Blababa [14]
3 years ago
9

many organize a classroom party. there are 20 of cold drinks at the party, 13 of which contain diet Pepsi, what is the probabili

ty that randomly selected drink will be a diet Pepsi? answer key
Mathematics
2 answers:
charle [14.2K]3 years ago
4 0

Answer:

so its either 13/20

Step-by-step explanation:

if you get this wrong sorry:(

Yanka [14]3 years ago
3 0
The answer is 13/20

Explanation:
20 is the denominator because it is how many drinks there are in total. 13 is the numerator because that’s how many are Diet Pepsi’s and you cannot simplify this. That’s why the answer in 13/20.

P.S whenever you can simplify this you should :)
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P(It will rain tomorrow) = 1 - P(It will not rain tomorrow) true or false
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The answer is TRUE


There are only two possible outcomes


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Thus the probability of one outcome dictates the probability of the other.


For example, imagine that


<em>P(It will rain tomorrow) = 1 </em><em> </em>(This means that you are 100% sure it will rain)


Then you can assure that


<em>P(It will rain tomorrow) = 1 - P(It will not rain tomorrow)</em>


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Enter the fraction 33100 as a decimal
Mariulka [41]

Answer:

0.33

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Juli2301 [7.4K]

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6 0
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Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
3 years ago
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