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ruslelena [56]
3 years ago
15

Explain three types of production technology defined by James D. Thomson and discuss what kind of structure (Mechanic Vs. Organi

c) best suits each of them?
Business
1 answer:
bija089 [108]3 years ago
6 0

Answer:

The three types of production technology defined by James D. Thomson are;

1. Long-linked technology

2 Mediating technology and,

3. Intensive technology.

Explanation:

James D. Thomson proposed that different types of technology would determine the organizational strategy used by some organizations. A Mechanistic structure is an organizational structure that requires a high degree of formalized and centralized activity. An Organic organizational structure is very dynamic and programmed to easily adapt to change. Three of the technology types proposed by him include;

1. Long-linked Technology- These are jobs that require an organized sequence. Task A is completed before task B and then Task C. They require formalization and an average level of complexity. An example is mass production of goods. It is an organic structure because changes can easily occur and it would therefore require dynamism.

2.Mediating Technology- These are jobs that unite the two different aspects of an organization, namely, the input and output units.  They require low complexity and high formalization. An example is in the banking industry where peoples input and output are simultaneously attended to. It is a mechanistic structure because it requires a very formal arrangement.

3. Intensive Technology- These are jobs that give specialized care to different types of problems. It can be found in the hospital setting. It requires high complexity and low formalization. It is a mechanistic structure because of the specialized care rendered and the high level of interdependence of the units involved .

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B

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3 years ago
a bacteria population starts with 200 bacteriaa and grows at a rate of r(t) = (450.268)e 1.12567t bacteria per hour. How many ba
Virty [35]

Answer:

11,513

Explanation:

Data provided in the question:

Initial bacteria = 200

Growth rate r(t) = (450.268)e^{1.12567t}

Now,

Total growth after 3 hours = \int\limits^3_0 {(450.268)e^{1.12567t}} \, dt

or

Total growth after 3 hours = 450.268\int\limits^3_0 {e^{1.12567t}} \, dt

or

Total growth after 3 hours =450.268[\frac{e^{1.12567t}}{1.12567}]^3_0

[ ∵ \int{d(e^x)}{dt}=\frac{e^x}{\frac{dx}{dt}}]

Thus,

Total growth after 3 hours = 400 × [{e^{1.12567t}]^3_0

or

Total growth after 3 hours = 400 × [{e^{1.12567(3)}-e^{1.12567(0)}]

or

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4 0
3 years ago
Which budgetary category changed the most between your old budget and your new budget? Why?
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The net savings changed the most, and this is because of the extra money coming in via total income. An extra $290.00 was added to the category.

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Answer:

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(1) Uncollectible Accounts Expense              18,600

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     ($600 + $18,000)

(2) Allowance for Doubtful Accounts              350

    Accounts Receivable—Fronk Co.                                350

(3)  Accounts Receivable—Fronk Co.             200

     Allowance for Doubtful Accounts                               200

     Cash                                                            200

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(4)  Cash                                                            400

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($600 - $400)*

3 0
3 years ago
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