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Xelga [282]
3 years ago
13

What solid is formed when rotating a square about a horizontal or vertical axis through the center of the square?

Mathematics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

Torus

Step-by-step explanation:

This particular solid is called a torus, and looks like a dough-nut. Note: The 2-D figure may appear on coordinate axes, from which you can obtain measurement information about the figure.

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Log(1+y) - log(1-y) = log x in 2 decimal places, express y in terms of x
GaryK [48]

Answer: y = \frac{x-1}{x+1}

Step-by-step explanation:

log(1+y) - log(1-y) = log x \\log\frac{1+y}{1-y} =log x\\x = \frac{1+y}{1-y}\\x(1-y)=1+y\\x-xy=1+y\\x-1 = xy+y\\y(x+1)=x-1\\y=\frac{x-1}{x+1}

6 0
3 years ago
Read 2 more answers
What are the solutions to the equation (2x – 5)(3x – 1) = 0?
user100 [1]

Answer: x=\frac{5}{2}, x=\frac{1}{3}

Explanation:

The equation is:

(2x-5)(3x-1)=0

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.

This means that we can solve separately for the two terms:

2x-5=0\\3x-1=0

Solving the first equation:

2x-5=0\\2x=5\\x=\frac{5}{2}

Solving the second equation:

3x-1=0\\3x=1\\x=\frac{1}{3}

8 0
3 years ago
Read 2 more answers
Simplify: 4sqrt400/4sqrt5. show your work
shusha [124]

4 sqrt(400) / 4 sqrt(5)

sqrt(400) =20

4 *20

--------

4 sqrt(5)

the 4's on the top and bottom cancel

20

--------

sqrt(5)


I was taught never to leave a sqrt in the denominator

so you need to multiply by sqrt (5) in the numerator and the denominator

20* sqrt(5)

--------

sqrt(5)* sqrt(5)


20* sqrt(5)

--------

5

= 4 sqrt(5)


4 0
3 years ago
Read 2 more answers
What is<br> -29=5(2a-1)+2a
pochemuha
<span>-29= 5 (2a-1) +2a

Start by distributing the terms....

- 29  = 10a - 5 + 2a 

Combine like terms...

- 29  = 12a - 5 

Add 5 to both sides ....

- 2 4 = 12 a

Divide both sides by 12 to get a by its self...

a = -2 
</span>
6 0
3 years ago
Read 2 more answers
If 5 is an element in the domain of f(x)= 8x-21/5, what is the corresponding element in the range?
Delvig [45]

Answer:

The corresponding element in the range when 5 is an element  in the domain is f(5)=\frac{179}{5}

Step-by-step explanation:

Given that the 5 is an element in the domain of f(x)

The function f is defined by f(x)=8x-\frac{21}{5}

To find the corresponding element in the range:

That is put x=5 in the given function f(x)

Therfore f(x) becomes

f(5)=8(5)-\frac{21}{5}

=40-\frac{21}{5}

=\frac{200-21}{5}

f(5)=\frac{179}{5}

Therefore corresponding element in the range when 5 is an element  in the domain is f(5)=\frac{179}{5}

6 0
3 years ago
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