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Xelga [282]
3 years ago
13

What solid is formed when rotating a square about a horizontal or vertical axis through the center of the square?

Mathematics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

Torus

Step-by-step explanation:

This particular solid is called a torus, and looks like a dough-nut. Note: The 2-D figure may appear on coordinate axes, from which you can obtain measurement information about the figure.

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Find the range of f(x) = -x + 4 for the domain (-3,-2,-1,1).
timofeeve [1]
The domain: D={-3;-2;-1; 1}

f(x) = -x + 4

subtitute

f(-3) = -(-3) + 4 = 3 + 4 = 7
f(-2) = -(-2) + 4 = 2 + 4 = 6
f(-1) = -(-1) + 4 = 1 + 4 = 5
f(1) = -1 + 4 = 3

Answer: The range: {3; 5; 6; 7}
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Which system is equivalent y=-2x^2 y=x-2
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The wording of your question suggests that there were answer choices.  Mind sharing them?

The system   <span>y=-2x^2 y=x-2 would be best written as:

</span><span>y=-2x^2 
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