Answer:
A,D,C would be your answers
Step-by-step explanation:
Answer:

Step-by-step explanation:
The formula for the accrued amount from compound interest is

1. Amount in account on 1 Jan 2015
(a) Data:
a = £23 517.60
r = 2.5 %
n = 1
t = 1 yr
(b) Calculations:
r = 0.025

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.
She must have had £23 944 in her account on 1 Jan 2015.
(2) Amount originally invested
(a) Data
A = £23 944.00

3. Summary
1 Jan 2014 P = £23 360.00
1 Jan 2015 A = 23 944.00
Withdrawal = <u> -1 000.00
</u>
P = 22 944.00
1 Jan 2016 A = £23 517.60
415
8*50 + 15
Mark brainliest please
Scale shows weight = 193
Weight of assistant = 135
Weight of dog = x
x = 193 - 135
x = 58
The dog weighs 58 pounds.
It would be 1 / (x + 2) (x - 4)