Answer:
15/7
Step-by-step explanation:
8/7 + 7/7 = 8+7 = 15
Therefore, the sum of 8/7 + 7/7 is equals to 15/7
Answer: A
Step-by-step explanation:
Uh I don’t think so.
Sorry! But stay safe! :)
Answer: The blue whale's weight is 150 times heavier than the narwhal's weight.
Step-by-step explanation:
Given: Weight of Blue whale = 
Weight of Narwhal = 
Number of times blue whale's weight is heavier than the narwhal's weight = 
![=\dfrac{3\times10^5}{2\times10^3}\\\\=1.5\times10^{5-3}\ \ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=1.5\times10^2\\\\=1.5\times100=150](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B3%5Ctimes10%5E5%7D%7B2%5Ctimes10%5E3%7D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E%7B5-3%7D%5C%20%5C%20%5C%20%5B%5Cdfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E2%5C%5C%5C%5C%3D1.5%5Ctimes100%3D150)
Hence, the blue whale's weight is 150 times heavier than the narwhal's weight.
Answer:
h(1.5) = 7.3 ft
h(10.3) = 24.9 ft
Step-by-step explanation:
Given the function h(d) = 2d + 4.3,
where:
h = height of the water in a fountain (in feet)
d = diameter of the pipe carrying the water (in inches)
<h3>h(1.5)</h3>
Substitute the input value of d = 1.5, into the function:
h(1.5) = 2(1.5) + 4.3
h(1.5) = 3 + 4.3
h(1.5) = 7 feet
The height of the water in a fountain is 7 feet when the diameter of the pipe is 1.5 inches.
<h3>h(10.3)</h3>
Substitute the input value of d = 10.3, into the function:
h(10.3) = 2(10.3) + 4.3
h(10.3) = 20.6 + 4.3
h(10.3) = 24.9 feet
The height of the water in a fountain is 24.9 feet when the diameter of the pipe is 10.3 inches.
<h3>Context of the solutions to h(1.5) and h(10.3):</h3>
The solutions to both functions show the relationship between the diameter of the pipe to the height of the water in a fountain. The height of the water in fountain increases relative to the diameter of the pipe. In other words, as the diameter or the size of the pipe increases or widens, the height of the water in a fountain also increases.
