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Shalnov [3]
3 years ago
9

Lucy drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Lucy drove hom

e, there was no traffic and the trip only took hours. If her average rate was miles per hour faster on the trip home, how far away does Lucy live from the mountains?
Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

The question is incomplete, the complete complete question will be:

Lucy drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 9 hours. When Lucy drove home, there was no traffic and the trip only took 4 hours. If her average rate was 40 miles per hour faster on the trip home, how far away does Lucy live from the mountains?

Lucy live at a distance of 288 miles from the mountains.

Step-by-step explanation:

DATA:

To the mts DATA:

Time = 9 hrs

Rate = r mph

Distance = 9r miles

From the mts DATA:

time = 4 hrs  

rate = r+40 mph  

distance = 4(r+40) miles

SOLUTION

Distance to = Distance from

9r = 4r + 160

5r = 160

r = 32 mph

RESULT:

Distance = 9r = 9*32 = 288 miles

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QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

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We divide through by 4 to obtain,


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d = 3


We put d=3 into equation (2) to get,



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QUESTION 2


The given system is

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3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



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QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

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We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




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Divide both sides by 3 to get,


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2(4) + 2b = 14


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2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



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The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


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11x - 3x = 18 - 2


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d = 4


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4 - e = 4

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