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vlada-n [284]
3 years ago
9

What is the sum 2/x^2 + 4/x^2

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0
The answer is 6/x^2

hope that helped!
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URGENT PLEASE HELP ME, ITS DUE IN A HOUR ​
Olegator [25]

Answer:

Area of gray region = 8x^2+8x-7

Step-by-step explanation:

The area covered by the furniture can be subtracted from the total area of the room to calculate the area of the gray region.

<em>Total</em> area of the room: 13x^2+7x-2

Area taken up by furniture: 5x^2-x+5

Area of gray region = total area of the room - area taken up by furniture

Area of gray region = 13x^2+7x-2-(5x^2-x+5)

Remember to distribute the negative sign:

Area of gray region = 13x^2+7x-2-5x^2+x-5

Combine like terms:

Area of gray region = 8x^2+8x-7

7 0
2 years ago
Read 2 more answers
!!PLEASE HELP ASAP!!<br><br> write in simplified radical form. assume all variables are nonnegative.
Ainat [17]

The answer should be B.

I used a calculator called photomath, its an app.

4 0
3 years ago
Apply the distributive property to factor out the greatest common factor.
mestny [16]

Answer:

1.

90+27

2.

90 = 9 x 10

3.

27 = 9 x 3

4.

So apply the distributive property would be:

90 + 27 = 9(10 + 3)

That would be it i'm sure glad to help

5 0
3 years ago
Find f(g(x)) for the functions f(x)=5sqrt(x+1)-2 and g(x)=x^2-1
aivan3 [116]

The value of the composite function f(g(x)) is 5x + 2

<h3>Composite functions</h3>

Composite functions are functions inside another function. Given the following functions:

f(x) = 5√x+1 - 2

g(x) = x² - 1

Determine the composite function f(g(x))

f(g(x)) = f(x² - 1)

f(x² - 1) = 5√x² - 1+1 - 2

f(x² - 1) = 5√x² + 2

f(x² - 1) = 5x + 2

Hence the value of the composite function f(g(x)) is 5x + 2

Learn more on composite function here: brainly.com/question/13502804

#SPJ1

5 0
2 years ago
hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhheeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelllllllll
GalinKa [24]

the answer is c:)

have a great rest of your night:D

8 0
3 years ago
Read 2 more answers
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