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Gala2k [10]
3 years ago
6

What is the equation of the line that passes through the point (-6,-6)(−6,−6) and has a slope of 2/3?

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0
The equation of the line that passes through the point (-6, -6) is “y = 2/3x - 2”.
elixir [45]3 years ago
4 0

Answer:

y = 2/3 x -2

Step-by-step explanation:

We have a point and a slope

y = mx+b

The slope, m, = 2/3

y = 2/3 x+ b

The point is (-6,-6)

Substitute this into the equation to solve for b

-6 = 2/3 (-6) +b

-6 = -4+b

Add 4 to each side

-6+4 = -4+4+b

-2 =b

Substitute into the equation

y = 2/3 x+ b

y = 2/3 x -2

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Is -5a solution to the equation 6x+5=5x+8+2x explain
VashaNatasha [74]

No.

Replace the x's with -5 and you get -25=-27 which is not a solution

8 0
3 years ago
How do you write 8409.08 in words?
attashe74 [19]

Answer:

eight thousand four hundred nine and eight hundredths

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Please answer I need help asap
strojnjashka [21]

Answer:

x=5

Step-by-step explanation:

\frac{x}{3} =\frac{9+6}{9} \\\\\frac{x}{3} =\frac{15}{9}

cross multiply

45=9x

solve for x by dividing 9 to get x alone

5=x

6 0
3 years ago
Read 2 more answers
The football club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $6.00
faust18 [17]

Answer:

Candy=x=2.8 bags

Cookies=3+2.8=5.8 bags

Step-by-step explanation:

Price

Bag of candy=$6.00

Bag of cookies=$4

Total sales=$40

Quantity

Let cookies=y=3+x

Let candy=x

There are 3 more bag of cookies than candy sold

Total sales=price*quantity of x + price*quantity of y

40=$4*(3+x) + 6*x

40=12+4x+6x

40=12+10x

40-12=10x

28=10x

X=28/10

x=2.8 bags

6 0
3 years ago
What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m
storchak [24]
Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √<span>[ 6m( 2 x radius - 6 m ) ] / 2 </span>
10 m = √<span> [ 6m( 2 x radius - 6 m ) ] </span>
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m²<span> = 6 m( 2 x radius - 6 m ) </span>
100 m²<span> = 12 m x radius - 36 sq m </span>
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m²<span> = 12 m x radius </span>
136 m²<span> / 12 m = 12 m x radius / 12 m </span>
<span>11.333 m = radius 
</span>
the area beneath an arc: 

<span>Area = r</span>²<span> x arc cosine [ ( r - h ) / r ] - ( r - h ) x </span>√<span>( 2 x r x h - h</span>²<span> ).
</span>
<span>r</span>²<span> = (11.333 m)</span>²<span> = 128.444 m</span>²<span> </span>
<span>r - h= 11.333 m - 6 m = 5.333 m </span>
<span>r * h = 11.333 m x 6 m = 68 m</span>²

<span>Area = 128.444 m</span>²<span> x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x </span>√<span>[ 2 x 68 m</span>²<span> - 36 m</span>²<span> ] </span>

<span>Area = 128.444 m</span>²<span> x arc cosine [ 0.4706 ] - 5.333 m x </span>√<span> [ 100m</span>²<span> ] </span>

<span>Area = 128.444 m</span>²<span> x 1.0808 radians - 5.333 m x 10 m </span>

<span>Area = 138.828 m</span>²<span> - 53.333 m</span>²<span> </span>

<span>Area = 85.4 m</span>²
6 0
4 years ago
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