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3 years ago

Please help! i couldnt copy and paste it into here so i decided to just screenshot it :)

Mathematics

2 answers:

zhuklara [117]3 years ago

8 0

Answer: Congruent

How;

Congruent angles are angles that have equal degree measure! Hope this helps!

s344n2d4d5 [400]3 years ago

6 0

I’m pretty sure congruent I’m not positive tho

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1)4-2(x + 19) = 50<br> 2)7(x-3)-14=70

zalisa [80]

2x+38=50
2x+38-38=50 -38
2x =12
2x/2 =12/2
x=6

8 0

3 years ago

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I just completed 12 questions on a test the progress bar shows 20% is complete how many total questions are on the test?

Mademuasel [1]

If 12 is 20%, then 24 is 40%, then 36 is 60%, then 48 is 80%, then 60 is 100%

So there are 60 questions on the test.

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3 years ago

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How much simple interest does $4,678.00 earn in 529 days at a rate of 7.3%? Round to the nearest cent.

statuscvo [17]

Answer:

$5,172.93

Step-by-step explanation:

We're gonna use the simple interest formula: P = A(1 + r(t))

P = final amount

A = starting amount (4,678)

r = rate (0.073)

t = years (529/365)

P = 4,678(1 + 0.073(529/365))

P = 5,172.9324

7 0

2 years ago

The sum of two integers is 54 and there difference is 16 what are the integers

Verizon [17]

54/2 = 27
27-8 = 19
27 + 8 = 35
19+35 = 54
35 - 19 = 16

4 0

3 years ago

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

LuckyWell [14K]

Answer:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

$df = n_1 +n_2 -2 = 10+15-2= 23$

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

$\bar X_1 = 1085$ sample mean for group 1

$\bar X_2 = 1034$ sample mean for group 2

$n_1 = 10$ sample size for group 1

$n_2 = 15$ sample size for group 2

$s_1 = 52$ sample deviation for group 1

$s_2 = 61$ sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: $\mu_1= \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

And the statistic is given by:

$t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

And replacing we got:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 10+15-2= 23$

And the p value would be:

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0

3 years ago