Question

Will mark brainliest please help ASAP Complete the square to find the vertex of this parabola x^2+14x-y-14=0

Answer 1

Answer:

the vertex is (-7, -63)

Step-by-step explanation:

x^2 + 14x - y - 14 = 0

x^2 + 14x = y + 14 (to isolate the x)

x^2 + 14x + 49 = y + 14 + 49

(x+7)^2 = y + 63

now we convert to vertex form, which is y = a(x – h)2 + k :

(x+7)^2 = y + 63

y = (x+7)^2 - 63

The vertex in vertex form is shown as (h, k) from y = a(x – h)2 + k, so in this case, h = -7 and k = -63. H is the x-coordinate as shown while k is the y-coordinate. Thus, the vertex is (-7, -63)