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makvit [3.9K]
3 years ago
11

How do you write 615,004 in word form

Mathematics
2 answers:
Vitek1552 [10]3 years ago
5 0

six hundred fifteen thousand four

koban [17]3 years ago
3 0
Six hundred fifteen thousand and four
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Earnings You work for 4 h on Saturday and 8 h on Sunday. You also receive a $50 bonus. You earn $164. How much did you earn per
marshall27 [118]
Hello there,

best way to do this one is set up your story line....

4h + 8h + 50 = 164$...

let's make this easier to look at and combine like terms..

12h + 50 = 164$...

Beautiful!!! Now let's try and get the h alone?...

minus 50 to both sides...

12h = 114$..

now divide both sides by 12...

H= 9.50$/hour

Looks like you made 9.50$ an hour but Hey, at least you got that bonus ;)
6 0
3 years ago
Line L passes through the point (-1, 1) and is PARALLEL to the line shown here. An equation of line L is
Pachacha [2.7K]
The problem cannot be fully solved because you did provide the line on which the line is parallel/ but i can give you the steps on how to solve it. first solve the slope of the parallel line by
m = ( y2 - y1 ) / ( x2 - x1 )
then the slope of that line is equal to slope of line passing pooint ( -1 , 1)
then solve the y intercept of the line using
y = mx + b
where b is the y intercept
then you will have the equation of the line
5 0
3 years ago
Read 2 more answers
2 yards and 60 inches in ratio
arsen [322]

2yrds:60in    is the answer


8 0
3 years ago
Find how many quarts of 6% butterfat milk and 1% butterfat milk should be mixed to yield 75 quarts of 3% butterfat milk.
IgorC [24]

Answer:

30 gallons of 6% milk, and 45 gallons of 1% milk.

Step-by-step explanation:

x=quarts of 6% butterfat

<h2>First, write an equation.</h2>

0.06x+0.01(75-x)=0.03*75

<h2>Multiply both sides by 100.</h2>

0.06x*100+0.01*100(75-x)=100*0.03*75

<h2>Simplify</h2>

6x+75-x=3*75

6x+75-x=225

<h2>Solve</h2>

5x=225-75=150

5x=150

x=30

75-30=45

So, we need 30 gallons of 6% milk, and 45 gallons of 1% milk.

8 0
3 years ago
Read 2 more answers
. Given that O is the centre of the following circle, find the values of the unknowns.​
alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

a^{2} + 5^{2} = 13^{2}

a^{2} + 25 = 169

a^{2} = 169 - 25

a^{2} = 144

\sqrt{a^{2}}=\sqrt{144}

a = 12

Now to find the value of 'b', i will use law of cosine,

c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }

12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta =   0.3846\\\beta  = cos^{-1}(0.3846)\\\beta = 67.38

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

3 0
3 years ago
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