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Vesna [10]
3 years ago
8

The vector 2v has the same direction as v but twice the magnitude of v

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

True

Step-by-step explanation:

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Graph f(x) = log5 (x-3).
Natali5045456 [20]

Step-by-step explanation:

We want to graph:

f(x) =\log_{5}(x - 3)

We first graph the parent function

g(x) =\log_{5}(x)

This parent function has x-intercept at (1,0) and it is asymptotic to the y-axis.

We then shift the graph of the parent function 3 units right, to obtain the graph of

f(x) =\log_{5}(x - 3)

The new x-intercept will be (4,0) and vertical asymptote will now be x=3.

See attachment.

6 0
3 years ago
Reduce the rate 80 miles per 4 hours to its unit rate and write the miles
VashaNatasha [74]

Answer:

20 mph.

Step-by-step explanation:

Unit rate = distance / time

= 80/4

= 20 miles per hour.

6 0
3 years ago
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Of the 528 clients at Bernie's salon, 122 of them have black hair. What is the probability that a randomly selected client at Be
EleoNora [17]

The probability that a randomly selected client at Bernie's salon has black hair is 61 / 264.

<h3>What is the probability?</h3>

Probability measures the odds that a stated event would occur. The odds the event happens lies between 0 and 1.

The probability that a client at Bernie's salon has black hair = number of clients with black hair / total number of clients

122 / 528 = 61 / 264

To learn more about probability, please check: brainly.com/question/13234031

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5 0
2 years ago
Plss help meeeeeeeeeeeeeeee
Olin [163]

Answer:

x=42

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the
Mazyrski [523]

Answer:

54 cm

Step-by-step explanation:

The area (A) of an equilateral triangle is

A = \frac{s^2\sqrt{3} }{4}  ( s is the side length ) then

\frac{s^2\sqrt{3} }{4} = 81\sqrt{3} ( multiply both sides by 4 to clear the fraction )

s²\sqrt{3} = 324\sqrt{3} ( divide both sides by \sqrt{3} )

s² = 324 ( take the square root of both sides )

s = \sqrt{324} = 18

Thus

perimeter = 3 × 18 = 54 cm

3 0
3 years ago
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