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kupik [55]
3 years ago
8

Find the volume of a sphere with surface area equal to 100π ft^2

Mathematics
2 answers:
Anni [7]3 years ago
8 0

Answer:

V=\frac{500}{3}\ \pi(ft^{3})

Step-by-step explanation:

Hello.

to find the volume of a sphere we must know its radius,

we don't know the radius but we have the area

A=4\pi r^{2} \\ \\isolating\ r\\\\A=4\pi r^{2}\\r=\sqrt{\frac{A}{4\pi } } \\r=\sqrt{\frac{100\ ft^{2} }{4\pi}} \\\\ r= \sqrt{25\ ft^{2} }\\ r=5\ ft\\

Now, replacing this value in the volume equation

V=\frac{4\pi r^{3} }{3} \\V=\frac{4\pi\ (5\ ft)^{3} }{3}\\ V=\frac{4\pi\ (125 ft^{3}) }{3}\\V=\frac{500}{3}\ \pi (ft^{3})\\\\\\

have a great day

yKpoI14uk [10]3 years ago
3 0
Surface area of sphere = 4 \pi  r^{2}

Volume of sphere = \frac{4}{3}  \pi  r^{3}

100 \pi =4 \pi  r^{2}

Therefore r = 5


Volume = \frac{4}{3}  \pi  *5^{3} =  \frac{500 \pi }{3}
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Identify the volume of the composite figure rounded to the nearest tenth. HELP PLEASE!!
nirvana33 [79]

Answer:

V = 115.3 ft³

Step-by-step explanation:

The left part of the figure shows a cube of side length 4.2 ft.  The volume of a cube is V = s³, where s is the side length.  Hence, the volume of this particular cube is V = (4.2 ft)³ = 74.088.

The volume of a pyramid is V = (1/3)(base area)(height).

Here V = (1/3)(4.2 ft)²(7 ft) = 41.16 ft³.

Summing up the two distinct areas, we get V = 41.16 ft³ + 74.088 ft³, or

V = 115.3 ft³ after rounding up to the nearest tenth.

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3 years ago
How many triangles can be constructed with sides measuring 7 cm, 6 cm, and 9 cm? more than one one none
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Answer:

none

Step-by-step explanation:


3 0
3 years ago
Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

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(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

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3 0
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Answer:

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5 x 1.5 + 1.5 (3) = 15

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Hope this helps!

If something is wrong, please let me know.

3 0
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Step-by-step explanation:

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