4 consecutive odd numbers....x, x + 2, x + 4, x + 6
2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7
x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13
ur numbers are : 7,9,11,13 <==
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The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0
<h3>How to determine the axis of symmetry?</h3>
The equation is given as:
y = 2x^2 + 3
Differentiate the above equation with respect to x
y' = 4x + 0
This gives
y' = 4x
Set the equation to 0
4x = 0
Divide both sides by 4
x = 0
Hence, the axis of symmetry is x = 0
Read more about axis of symmetry at:
brainly.com/question/1349456
Answer:
C
Step-by-step explanation:
just took that