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Anvisha [2.4K]
3 years ago
6

The mean of a data set of 6 numbers is 8. The mean of a different data set of 6 numbers is 20. Whats the mean of the combined da

ta sets?​
Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

HERE IS YOUR ANSWER HOOMAN:

8

STEP BY STEP EXPLANATION FAM:

We have a set of four numbers and the mean is 5. We can see that the sum of the values is 20:

\frac{20}{4}=5

We have another set of three numbers whose mean is 12. We can write that as:

\frac{36}{3}=12

To find the mean of the seven numbers together, we can add the values together and divide by 7:

\frac{20+36}{7}=\frac{56}{7}=8

HOPE DIS HELPED FAM  

w(゚Д゚)w

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nexus9112 [7]

Answer:

A mathematical equation is an equation with zero or one variables (e.g., 9 = 6 + 3; 9 = x + 3), whereas an algebraic equation

Step-by-step explanation:

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2 years ago
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The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000
Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

P = P_0 \times e^{rt}

where P is the population after time t, P_0 is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

2 P_0 = P_0 \times e^{r 1/3}

2 = e^{r \; 1/3}

ln 2 = r \; 1/3

ln 2 \times 3 = r

2.08 \% = r

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

90000 = P_0 \times e^{2.08 \; 5/3}

\frac{9000}{e^{2.08 \; 5/3}} = P_0

2810 = P_0

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

P = 2810 \times e^{2.08 \; 5}

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3 0
3 years ago
Ten samples of coal from a northern appalachian source had an average mercury content of 0.242 ppm with a standard deviation of
Dovator [93]
The confidence interval is from 0.2191 to 0.2649, given by

0.242\pm0.0229.

The z-score we need is found by first subtracting the confidence level from 1:
1 - 0.95 = 0.05

Divide that by 2:
0.05/2 = 0.025

Subtract that from 1:
1 - 0.025 = 0.975

Look this up in the middle of a z-table (http://www.z-table.com) and we see that the z-score is 1.96.

Now our confidence interval is given by
\overline{x} \pm z\times \frac{\sigma}{\sqrt{n}}
\\
\\0.242\pm 1.96 \times (\frac{0.037}{\sqrt{10}})
\\
\\0.242 \pm .0229
\\
\\0.242-0.0229=0.2191
\\
\\0.242+0.0229 = 0.2649
5 0
3 years ago
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
serious [3.7K]

Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

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Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is |S| = C(40,6).

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The total number of ways to select the 6 incorrect numbers from 34 numbers is:

|E| = C(34,6)

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is  

P(E) = \frac{|E|}{|S|}

         = \frac{C(34, 6)}{C(40, 6)}\\\\= \frac{1344904}{3838380}\\\\=0.35

Therefore, the probability is 0.35

Check the attached files for additionals  

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