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2 years ago

5

Find the value of x. Round your answer to the nearest tenth. Help please!

1 answer:

sp2606 [1]2 years ago

4 0

Use the formula c^2 = a^2 + b^2
9^2 = x^2 + 7^2
81 = x^2 + 49
x^2 = 32
x = 5.7 (rounded)

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I NEED ANSWER ASAP! I WILL GIVE BRAINELIEST!!!!!! Construct a right triangle whose legs are in the ratio 3:4. What are the ratio

Gala2k [10]

Answer:

3 : 5, 4: 5

Step-by-step explanation:

Let the common multiplier of the given ratios be x.

Therefore, lengths of the legs of right triangle would be 3x and 4x

By Pythagoras Theorem:

${hyp}^{2} = {(3x)}^{2} + {(4x)}^{2} \\ = 9 {x}^{2} + 16 {x}^{2} \\ = 25 {x}^{2} \\ hyp = \sqrt{25 {x}^{2} } \\ hyp = 5x \\ \\ ratios \: of each \: leg \: to \: the \: hypotenuse \\ \frac{3x}{5x} = 3 : 5 \\ \\ \frac{4x}{5x} = 4 : 5$

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3 years ago

hot dog buns are sold in packages of 8 and 12. taro bought 192 total buns for a party. This is represented by the function 8x +

Lelu [443]

Here is the graphical representation of the function you provide.

You can see the the points in which the line intersects each axis.

Every point in the line is a possible option for which hot dog package was bought.

For example, Taro might have bought 0 of the packages of 8, and 16 packages of 12.

or He might've bought zero packages of 12, and 24 packages of 8.

6 0

3 years ago

Radius of the circle is 8cm, find the volume and surface area

nasty-shy [4]

Answer:

am not sure but I think the answer is79.02

4 0

2 years ago

What is 7/2 divided by 49/4?

ruslelena [56]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

$\frac{7}{2}$ ÷ $\frac{49}{4}$ needs to be flipped and multiplied.

It will become $\frac{7}{2}$ · $\frac{4}{49}$ .

Simplify the fractions by replacing 7 with 1 and 49 with 7, since 7 is 1/7 of 49. Then, turn the 2 into a 1 and the 4 into a 2, since 2 is half of 4.

You will be left with 1 · $\frac{2}{7}$ , which equals $\frac{2}{7}$

4 0

2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago