2 years ago

Find the value of x. Round your answer to the nearest tenth. Help please!

Mathematics

1 answer:

sp2606 [1]2 years ago

4 0

Use the formula c^2 = a^2 + b^2
9^2 = x^2 + 7^2
81 = x^2 + 49
x^2 = 32
x = 5.7 (rounded)

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<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_3%7Bx%5E%7B2%7D-x%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits

melisa1 [442]

Answer:

$\frac{53}{6}$

Step-by-step explanation:

$\int\limits^4_3 {x^2-x} \, dx$

= [ $\frac{x^3}{3}$ - $\frac{x^2}{2}$ ] ← evaluate for upper limit - lower limit

= ( $\frac{64}{3}$ - $\frac{16}{2}$ ) - ( $\frac{27}{3}$ - $\frac{9}{2}$ )

= $\frac{64}{3}$ - 8 - 9 + $\frac{9}{2}$

= $\frac{155}{6}$ - 17

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Answer is in a ph $^{}$ oto. I can't attach it he $^{}$ re, but I uploaded it to a fi $^{}$ le hosting. link below! Good Luck!

bit. $^{}$ ly/3a8Nt8n

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3 years ago

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VladimirAG [237]

Answer:

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Step-by-step explanation:

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