4x-7x= 13
⇒ -3x= 13
⇒ x= 13/(-3)
⇒ x= -13/3
The final answer is x= -13/3~
With the b2+b- 12 your gonna want to do this
b2+b-12
b2+4b-3b-12
which is the sum product
after doing that you wanna common the factors from the two pairs. Which is b2+4b-3b-12 then you do you parentheses around b(b+4)-3(b+4) just like that after you do that then you rewrite it in factored form b(b+4)-3(b+4) you then want to rewrite it to this (b-3)(b+4) after that your solution will be (b-3)(b+4) for the first one.
Example:
The sum of two consecutive integers is -15. What is the product of the two integers?
x = 1st consecutive integer
x + 1 = 2nd consecutive integer {consecutive integers increase by 1}
x + x + 1 = -15 {the sum of two consecutive integers is -15}
2x + 1 = -15 {combined like terms}
2x = -16 {subtracted 1 from each side}
x = -8 {divided each side by 2}
x + 1 = -7 {substituted -8, in for x, into x + 1}
-8 and -7 are the two consecutive integers
Their product is 56.
Answer:
7/24
Step-by-step explanation:
you have to have a common denominator so you multiply one denominator to the opposite numerator and denominator and vice versa. So for 2/3 you should get 16/24 and for 3/8 you should get 9/24. Then you subtract 9 from 16 and get 7. So the answer is 7/24
