Answer:
1st pair x=-7 and -9; 2nd pair x=2 and y=2; 3rd pair x=-1 and y=0; 4th pair x=-3 and y= 2; 5th x=-2 and y=-1; All others are not clearly written
Step-by-step explanation:
method for simultaneous equation are substitution, elimination or matrix methods
<h3>First let us know –</h3>
- What is complementary angle ?
When sum of two angles is 90°, then each of those two angles will be considered to be the complementary angle of each other.<u>Example</u> : 60° and 30° are two angles, and their sum is 90°. So, 60° and 30° are complementary angles.
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<h3><u>Explanation</u> :-</h3>
- Measure of an angle is 13.8° more than the measure of it's complementary angle. We are asked to find measure of each angle!
<h3><u>Solution</u> :-</h3>
- One of the complementary angles be "x" . Then the other angle becomes " (x + 13.8)° "
- Sum of these two angles is equal to 90° . Since they are complementary angles.
<u>Then</u> –
- The measures of the two given angles is 38.1° and 51.9°.
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Here's the key to unlock the whole problem and make it crumble in a pile of dust at your feet:. A tangent is perpendicular to the radius at the point where the tangent touches the circle. /// Connect point O to the point way outside, and you have two congruent right triangles face to face. The angles inside each one add up to 180. Each angle at O is half of 134, and each angle at the point way outside is half of 'x'. I bet you can do it now.
Answer:
the y intercept is -2
Step-by-step explanation:
the y intercept is always the value on the end
9514 1404 393
Answer:
- cable length: 300.2 ft
- anchor distance: 193.0 ft
Step-by-step explanation:
The side given is opposite the given angle. We want to find both the hypotenuse and the adjacent side in the right triangle that models the geometry.
Sin = Opposite/Hypotenuse
sin(50°) = (230 ft)/h
h = (230 ft)/sin(50°) ≈ 300.24 ft
The length of the cable must be about 300.2 feet.
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Tan = Opposite/Adjacent
tan(50°) = (230 ft)/d
d = (230 ft)/tan(50°) ≈ 192.99 ft
The cable must be anchored about 193.0 ft from the tower.