I'm going to assume the 4 and 3 are exponents and the expression is
.
The first step is to separate the coefficients of 3 and -6 from the variables and to multiply those as normal:
![3 \cdot (-6) = -18](https://tex.z-dn.net/?f=3%20%5Ccdot%20%28-6%29%20%3D%20-18)
As for the variables, you want to recognize that
means
and
means
, so
![a^4 \cdot a^3 = \left( a \cdot a \cdot a \cdot a\right) \cdot \left(a \cdot a \cdot a\right)](https://tex.z-dn.net/?f=a%5E4%20%5Ccdot%20a%5E3%20%3D%20%5Cleft%28%20a%20%5Ccdot%20a%20%5Ccdot%20a%20%5Ccdot%20a%5Cright%29%20%5Ccdot%20%5Cleft%28a%20%5Ccdot%20a%20%5Ccdot%20a%5Cright%29)
In total, there are 7 a's being multiplied, so
![a^4 \cdot a^3 = a^{4+3} = a^7](https://tex.z-dn.net/?f=a%5E4%20%5Ccdot%20a%5E3%20%3D%20a%5E%7B4%2B3%7D%20%3D%20a%5E7)
Putting this all together, we have:
![\left(3a^4\right)\left(-6a^3\right) = 18a^7](https://tex.z-dn.net/?f=%5Cleft%283a%5E4%5Cright%29%5Cleft%28-6a%5E3%5Cright%29%20%3D%2018a%5E7)
Answer:
brainliest plsssss
Step-by-step explanation:
4−7i−(3+2i)
=1−9i
Answer: yes they are equivalent
Step-by-step explanation:
No matter how the number is placed in the equation if it is the same numbers they are equivalent
Answer:
5.5, 9.5
Step-by-step explanation:
Let x and y be the numbers
x+y = 15
x-y = 4
Add the two equations together to eliminate y
x+y = 15
x-y = 4
------------------
2x = 19
Divide by 2
2x/2 =19/2
x = 9.5
Now find y
x+y = 15
9.5+y = 15
Subtract 9.5
x = 15-9.5
x =5.5