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spin [16.1K]
3 years ago
10

−7m^5 + 3m^3 + 5m^2 plz show work

Mathematics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:See below

Step-by-step explanation:See below

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You buy a car for 1000 every year it loses 40% of its value
VladimirAG [237]

Answer:

\displaystyle V_n=V_o\left(0.60\right)^n

<em>The car is worth 360 after two years</em>

Step-by-step explanation:

<u>Model For Depretiation</u>

Assume the situation of something that has an initial value Vo and loses its value by a x% every year. The first year it will lose

\displaystyle \frac{xV_o}{100}

and it will have a new value of

\displaystyle V_1=V_o-x\frac{V_o}{100}=V_o\left(\frac{100-x}{100}\right)

Next year it will have a value of

\displaystyle V_2=V_o\left(\frac{100-x}{100}\right)^2

Since x=40%, we can deduct the general formula

\displaystyle V_n=V_o\left(0.60\right)^n

For n=2

\displaystyle V_2=1000\left(0.60\right)^2

V_2=360

7 0
3 years ago
Find the value of the missing variables.
dsp73

Answer:

x^{\circ}=35^{\circ}\\ \\y^{\circ}=55^{\circ}

Step-by-step explanation:

The measure of arc which the right triange cuts from the circle is 70^{\circ}, this means the central angle has the same measure.

Angle with measure x^{\circ} is inscribed angle subtended on the given arc. Its measure is half the measure of the central angle, hence

x^{\circ}=\dfrac{1}{2}\cdot 70^{\circ}=35^{\circ}

Angles with measures x^{\circ} and y^{\circ} are complementary angles (add up to 90°), so

y^{\circ}=90^{\circ}-35^{\circ}=55^{\circ}

6 0
3 years ago
26.
boyakko [2]

Answer:

boom bam ba boom bam ba

4 0
2 years ago
180/9times10^-5 what’s the answer to this in scientific notation
Lady bird [3.3K]

Answer:

180/9= 20

20x10^-5= 0.00020

Step-by-step explanation:

Move the decimal point 5 times to the left :)

7 0
3 years ago
A cone has a radius of 3 units and a height of 4 units.
Alika [10]

Answer:

1. V = 37.7

2. V =603.19

Step-by-step explanation:

1. V = (3.14)×3^2 4/3

V =37.7

2. V=(3.14)×(3×4)^2 4/3

V = (3.14)×12^2 4/3

V = 603.19

7 0
3 years ago
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