Answer:
-4, 5/8, 2.9 3
Step-by-step explanation:
The answer is 81 because 27 x 3
That Equals = -60i. Hope im right :) Good luck
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
9514 1404 393
Answer:
H the range is all real numbers
Step-by-step explanation:
The arrows on the ends of the curve mean the curve extends to infinity. Then the domain (x-extent) is -3 to infinity.
The range (y-extent) is -infinity to infinity, <em>all real numbers</em>.
The appropriate description is ...
H The range is all real numbers
