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Vikentia [17]
2 years ago
8

Consider the functions f(x)=x−7 and g(x)=4x3. What is f(x)+g(x)?

Mathematics
2 answers:
ira [324]2 years ago
7 0

Answer:

I attached a picture

Step-by-step explanation:

hope this helps!!! :)

Margarita [4]2 years ago
5 0

Answer:

4x^3 + x - 7 if g(X) is 4x^ 3

Step-by-step explanation:

f(X) =x-7

g(X) =4x ^3

f(X) + g(X) = x - 7 + 4x^3

= 4x^3 + x -7

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Which measure is of an angle that is conterminal with a 95 degree angle
timofeeve [1]

Answer: Choice B

95 - 1080n for any integer n

=================================================

Explanation:

Notice how 1080 is a multiple of 360 since 360*3 = 1080. The other values 1450, 780 and 340 are not multiples of 360. For example 1450/360 = 4.02777 approximately. We need a whole number result to show it is a multiple.

Therefore, choice B shows subtracting off a multiple of 360 from the original angle 95. In my opinion, it would be better to write 95+360n or 95-360n to make it more clear we are adding or subtracting multiples of 360.

Choice B will find coterminal angles, but there will be missing gaps. One missing coterminal angle is 95-360 = -265 degrees. So again, 95-360n is a more complete picture. I can see what your teacher is going for though.

8 0
3 years ago
Show me how to Graph y = 3x + 2
melisa1 [442]
This what it should look like. did you need the steps or no ?

4 0
3 years ago
After Halloween, Chad had 213 bags of candy. If Chad gives 123 bags of candy to his little brother, how many bags of candy will
stellarik [79]

Answer:

90 bag

Step-by-step explanation:

no of bags will he have left=213-123

=90 bags of candy

3 0
2 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
Find the GCF of the terms for each polynomial, and factor<br><br> 12n^(3) - 8n
wolverine [178]

Answer:

4n

Step-by-step explanation:

I don't know if I did it right but I hope I did sorry if wrong

5 0
2 years ago
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