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igor_vitrenko [27]
3 years ago
5

The week before , Jack spent 22 1/4 hours on his homework, How long did Jill spent doing homework?

Mathematics
1 answer:
qwelly [4]3 years ago
5 0
There is no way of knowing
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Write an equation of the line below.
otez555 [7]

Answer:

im not exactly sure but i think it would be y=1x-2

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2 years ago
Probability of impossible event is ………… [. ]<br><br>a) 0 b) 100% c) 1 d) both b &amp; C​
Andre45 [30]

Answer:

0

Step-by-step explanation:

7 0
3 years ago
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Writethecoordinatesoftheverticesafteradilationwithascalefactorof 1 5 ,centeredattheorigin. y x -10 10 -10 10 0 S T U S(5, -10) →
densk [106]

Answer:

The answer is below

Step-by-step explanation:

Write the coordinates of the vertices after a dilation with a scale factor of 1/5 , centered at the origin.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

Dilation is the reduction or enlargement in the size of an object by a scale factor (k). If k > 1, it is an enlargement and if k < 1, it is a reduction. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

Therefore, if the vertices are dilated with a scale factor of 1/5 , centered at the origin. The new point is:

S(5, -10) → S′(1 , -2) T(10, -10) → T′(2 , -2) U(5, 10) → U′(1 , 2)

6 0
3 years ago
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Find the missing term for me plz nd thx
RUDIKE [14]

Answer:

6x

Step-by-step explanation:

3*2x=6x

8 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' − 2y = (t − 4), y(0) = 0
yulyashka [42]

Using the Laplace transform, the value o y' − 2y = (t − 4), y(0) = 0 is⇒y(t) = 0 e^-t + u(t -1)e^1-t

Laplace rework is an critical rework approach that is in particular useful in fixing linear normal equations. It unearths very huge applications in  regions of physics, electrical engineering, control optics, arithmetic and sign processing.

y' − 2y = (t − 4),

y(0) = 0

Taking the Laplace transformation of the differential equation

⇒sY(s) - y (0) + Y(s) = e-s

⇒(s + 1)Y(s) = (0+ e^-s)/s + 1

⇒y(t) = L^-1{0/s+1} + {e ^-s/s + 1}

⇒y(t) = 0 e^-t + u(t -1)e^1-t

The Laplace remodel method, the feature within the time area is transformed to a Laplace characteristic within the frequency domain. This Laplace feature will be inside the shape of an algebraic equation and it can be solved easily.

Learn more Laplace transformation here:-brainly.com/question/14487437

#SPJ4

4 0
2 years ago
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