I believe that would be a decomposer
The mass percentage of KCl solution is 21.34%
Calculation,
Given molality of KCl aqueous solution = 3. 64 m = 3. 64 mole/ Kg
It means 3. 64 mole of solute present in 1Kg of solvent
or , 3. 64 mole of solute present in 1000 g of solvent ( water )
Mass of solute ( KCl ) = 3. 64 mole×74.55 g/mole =271.3 g
The total mass of solution ( KCl + water ) = 271.3 g + 1000 g = 1271.3 g
Mass percentage is equal to percentage of mass of solute present in total mass of solution.
Mass percentage = 100×271.3 g/1271.3 g = 21.34%
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We are given with a mixture of sand and table sugar. The mixture has a mas s of 3.84 grams. After recovery, it was found out that there is 1.43 grams of sand. The amount of table sugar then is 3.84-1.43 or 2.41 grams. This is equal to 2.41/3.84 or 62.76% by mass/
The volume that is needed to react completely with 0.100 mol of lead nitrate is 0.400 L. It is because 2 moles of HCl are required for every mole of lead nitrate.
2 x 0.100 mole Pb(NO₃) = 0.200 mole HCl
0.200 mol HCl = L x 0.500 M
Explanation:
Iron atom is been oxidised as it losses 2 electron to form 2 + ion.
