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3 years ago

The apparent westward movement of a planet against the background of stars is called ____. (1 point)

Chemistry

2 answers:

Tamiku [17]3 years ago

6 0

Answer:

retrograde motion

Explanation:

Natali5045456 [20]3 years ago

3 0

Answer:

<u>retrograde motion </u>

Explanation:

All the planets have direct motion or progade motion i.e. they move in eastward direction around the Sun. The exceptions are Venus and Uranus which apparently move westwards. This is type of motion is known as retrograde motion. Venus and Uranus move opposite to the other planets motion against the background of stars.

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If an object goes through a chemical reaction but does not change in mass that object has

eimsori [14]

Answer:

The law of conservation of mass

Explanation:

The law of conservation of mass

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2 years ago

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Explanation:

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Which of the following can be said about the boiling point of a liquid

Elodia [21]

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3 years ago

If you feed 100 kg of N2 gas and 100 kg of H2 gas into a

torisob [31]

Answer : The mass of ammonia produced can be, 121.429 k

Solution : Given,

Mass of $N_2$ = 100 kg = 100000 g

Mass of $H_2$ = 100 kg = 100000 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $H_2$ = 2 g/mole

Molar mass of $NH_3$ = 17 g/mole

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{100000g}{28g/mole}=3571.43moles$

$\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{100000g}{2g/mole}=50000moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2+3H_2\rightarrow 2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $N_2$ react with 3 mole of $H_2$

So, 3571.43 moles of $N_2$ react with $3571.43\times 3=10714.29$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 3571.43 moles of $N_2$ react to give $3571.43\times 2=7142.86$ moles of $NH_3$