How many unique 1h nmr and 13c nmr signals exist for each compound?
1 answer:
The structures along with their codes are given below.
For Compound A:
# of ¹H signals: 3 (as both side chains from carbonyl positions are same)
# of ¹³C signals: 4
For Compound B:
# of ¹H signals: 3 (the two methyl groups of isopropyl are equivalent)
<span># of ¹³C signals: 4
</span>
For Compound C:
# of ¹H signals: 2 (as both side chains from carbonyl positions are same)
# of ¹³C signals: 3
For Compound D:
# of ¹H signals: 3
# of ¹³C signals: 4
For Compound A:
# of ¹H signals: 3 (as both side chains from carbonyl positions are same)
# of ¹³C signals: 4
For Compound B:
# of ¹H signals: 3 (the two methyl groups of isopropyl are equivalent)
<span># of ¹³C signals: 4
</span>
For Compound C:
# of ¹H signals: 2 (as both side chains from carbonyl positions are same)
# of ¹³C signals: 3
For Compound D:
# of ¹H signals: 3
# of ¹³C signals: 4
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The question has missing information.
The options are given below.
a.The equilibrium lies far to the right
b. The reaction will proceed very slowly
c. The reaction contains significant amounts of products and reactants at equilibrium.
d. The equilibrium lies far to the left
Answer : The correct answer is option c: The reaction contains significant amounts of products and reactants at equilibrium.
Explanation :
Option a is not correct because for equilibrium to lie far to the right, we need a large value of keq ( Keq >>> 1 ), but the keq value is small.
option b is also not correct because in order to predict the speed of the reaction, we need more information. The speed of the reaction cannot be predicted using Keq value.
Option d is not correct because for Keq to lie far to the left, it has to be very very small. ( Keq <<< 1)
The value of equilibrium constant is given as 4.24. This value is very near to 1.
Equilibrium constant for this reaction is calculated as
When Keq = 1,
That means concentrations of products and reactants are equal.
Since the keq value for our reaction is very close to 1, we can say that , there are significant amounts of reactants and products at equilibrium.
Therefore option C is the correct option.