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2 years ago

Loan

Mathematics

1 answer:

diamong [38]2 years ago

5 0

B

Explanation: I guessed and it was right

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ST | PR. Find QR. 35 28 40

Greeley [361]

Answer:

The answer is 47

Step-by-step explanation:

I'm pretty sure this is the answer :)

40 - 28 = 12

35 + 12 = 47

Proof: 35 - 28 = 7

47 - 40 = 7

8 0

2 years ago

Jake’s map shows the distance from the Bake Stars Cafe to the restaurant supply store as 3 centimeters. If the scale of the map

Stolb23 [73]

Answer:

The real distance from shop to store is 24 kilometers.

Step-by-step explanation:

Given:

Distance from the Bake Stars Cafe to the restaurant supply store on map = 3 cm

Also Given:

Scale of the map 1 cm = 8 km

We need to find the real distance from the shop to the store.

Solution:

Now we know that;

Distance from shop to store on map =3 cm

1 cm = 8 km

3 cm = Real distance from shop to store

By using Unitary method we get;

Real distance from shop to store = $8\times3 =24 \ km$

Hence The real distance from shop to store is 24 kilometers.

8 0

3 years ago

A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f

tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

= 180° - (45° + 120°)

= 180° - 165°

= 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

$\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}$

$\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

$\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

PR = $\frac{12\text{sin}(120)}{\text{sin}(15)}$

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0

3 years ago

Solve 3x2+7x+1=0 using the quadratic formula.

NNADVOKAT [17]

Answer:

$x=\frac{-7+-\sqrt{37} }{6}$

Step-by-step explanation:

This (±) goes between the $-7$ and $\sqrt{37}$

$3x^{2} +7x+1=0$

$ax^{2} +bx+c$

$-b$ ± $\sqrt{b^2-4ac}$ /2a

$-7$ ± $\sqrt{(7)^2-4(3)(1)}$ /2(3)

$-7$ ± $\sqrt{49-12}$ /6

$-7$ ± $\sqrt{37}/6$

7 0

2 years ago

Simplify the expression

Hitman42 [59]

Answer:

r^12 t^12

Step-by-step explanation:

4 0

2 years ago